游戏达人
![Rank: 7](static/image/common/star_level3.gif) ![Rank: 7](static/image/common/star_level2.gif) ![Rank: 7](static/image/common/star_level1.gif)
- 贡献度
- 189
- 金元
- 16082
- 积分
- 2364
- 精华
- 0
- 注册时间
- 2010-6-8
|
Place twice as much iron as lead in chest 1.
Place the same amount of iron in chest 2, then add 1 more. But place twice as much lead in chest 2 as you place in chest 3.
Place four times more lead than iron in chest 3.
Place half as much lead in chest 4 as is contained in chests 2 and 3 together. To determine how much iron you must place in chest 4 , caculate the difference between the amounts of iron contained in chests 1 and 3.
我根据自己的"理解"列了个方程组,如下(两个∑为砝码总数,我点了好几次,确认无误. L为lead数, I为iron数):
L1=2I1
I2=I1+1
L3=2L2
L3=4I3
L4=(L2+L3)/2
I4=| I1-I3 |
∑L=20
∑I=13
I,L∈N
结果...该方程组无解. 估计是我理解错了上面的某些句子. 求英语帝帮助~ |
|