废墟神殿里放砝码的问题....
Place twice as much iron as lead in chest 1.Place the same amount of iron in chest 2, then add 1 more. But place twice as much lead in chest 2 as you place in chest 3.
Place four times more lead than iron in chest 3.
Place half as much lead in chest 4 as is contained in chests 2 and 3 together. To determine how much iron you must place in chest 4 , caculate the difference between the amounts of iron contained in chests 1 and 3.
我根据自己的"理解"列了个方程组,如下(两个∑为砝码总数,我点了好几次,确认无误. L为lead数, I为iron数):
L1=2I1
I2=I1+1
L3=2L2
L3=4I3
L4=(L2+L3)/2
I4=| I1-I3 |
∑L=20
∑I=13
I,L∈N
结果...该方程组无解. 估计是我理解错了上面的某些句子. 求英语帝帮助~ 其实没有你认为的那么复杂，简单翻译一下，然后告诉你答案：
Place twice as much iron as lead in chest 1.
第一个箱子里，铁砝码的数量是铅砝码的两倍。
Place the same amount of iron in chest 2, then add 1 more. But place twice as much lead in chest 2 as you place in chest 3.
第二个箱子里，铁砝码的数量等于第一个箱子里铁砝码数量再加一个，但是铅砝码的数量是第三个箱子里铅砝码数量的两倍。
Place four times more lead than iron in chest 3.
第三个箱子里，铅砝码的数量是铁砝码的数量的四倍。
Place half as much lead in chest 4 as is contained in chests 2 and 3 together. To determine how much iron you must place in chest 4 , caculate the difference between the amounts of iron contained in chests 1 and 3.
第四个箱子里，铅砝码的数量是第二个和第三个箱子里铅砝码数量总和的一半，铁砝码的数量则是第一个箱子与第三个箱子里铁砝码数量之差。
由上面的提示可知：
箱子一：铅砝码两个、铁砝码四个
箱子二：铅砝码八个、铁砝码五个
箱子三：铅砝码四个、铁砝码一个
箱子四：铅砝码六个、铁砝码三个 膜拜高玩，在神庙被一堆mm围x死的人路过。 我是让那个NPC做的 自己懒得做了 翻译你看上面的，要算的话这样：
设第一个箱子x个铅，第三个箱子y个铁，则
箱子1：2x铁，x铅
箱子2：2x+1铁，8y铅
箱子3：y铁，4y铅
箱子4：2x-y铁，6y铅
铅一共20个，铁一共13个
18y+x=20
6x+1=13
得x=2,y=1 Place four times more lead than iron in chest 3.
第三个箱子里，铅砝码的数量是铁砝码的数量的四倍。
这句是重点...... 自己拿张纸 先翻译好 然后动笔画四个圈圈试一试分配 我分了5分钟就出来了。很简单的。
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